RESOUDRE LES EQUATIONS SUIVANTES a. 2x + 10 = 0 b. 40x - 22 = 10x + 8 c. [tex] \frac{1}{2}x + \frac{1}{3} = \frac{1}{4}x + \frac{1}{5} [/tex] d. x² = 121 e.
Mathématiques
Liindsay
Question
RESOUDRE LES EQUATIONS SUIVANTES
a. 2x + 10 = 0
b. 40x - 22 = 10x + 8
c. [tex] \frac{1}{2}x + \frac{1}{3} = \frac{1}{4}x + \frac{1}{5}
[/tex]
d. x² = 121
e. 2x² + 1 = 289
f. (x+7)² = 64
a. 2x + 10 = 0
b. 40x - 22 = 10x + 8
c. [tex] \frac{1}{2}x + \frac{1}{3} = \frac{1}{4}x + \frac{1}{5}
[/tex]
d. x² = 121
e. 2x² + 1 = 289
f. (x+7)² = 64
1 Réponse
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1. Réponse nonoduchablais
Salut :)
a. 2x + 10 = 0
2x = -10
x = -10/2
x = (-5)
b. 40x - 22 = 10x + 8
40x - 22 -10x = 8
30x = 8 + 22
30x = 30
x = 30/30
x = 1
c.
2/4x + 5/15 = 1/4x + 3/15
2/4x + 5/15 - 1/4x = 3/15
1/4x = 3/15 - 5/15
1/4x = -2/15
x = -2/15 x 1/4
x = -1/30
d. x² = 121
x = √121
x = 11
e. 2x² + 1 = 289
2x² = 289 - 1
2x² = 288
x² = 288/2
x² = 144
x = √144
x = 12
f. (x+7)² = 64
(x + 7)² = 8²
x + 7 = √8²
x + 7 = 8
x = 8 - 7
x = 1
J'espère t'avoir aidé(e)! :)