Mathématiques

Question

calculer les expressions suivantes et donner le résultat sous forme de fraction irréductible. (mathématique)
ssvvpp c'est trop dure sa fais des heures je galère deçue

1) 5/7+(2/7-5)

2) 3/4+2×5+1/2

3)(3/2+2)(5+1/2)

4) 4/5×(5/4+1)-3/10

5) -5/7+-2/7×1/3

6) 8+21×2/3

7) 7/3-4/3÷2/5

8) 2/5+3/5+(1-1/10)

9) (1/9-3/5)(8/5+7/9)

merci à se qui me répondra svp j'ai a faire sa pour demain.

1 Réponse

  • Bonjour,

    1) 5/7+(2/7-5)

    = 5/7 + [2/7 - (5 x 7) / (1 x 7)]

    = 5/7 + (2/7 + 35/7)

    = 5/7 + 35/7

    = 42/7

    = (7 x 6) / (7 x 1)

    = 6

    2) 3/4+2×5+1/2

    = 3/4 + 10 + 1/2

    = 3/4 + (10 x 4) / (1 x 4) + (1 x 2) / (2 x 2)

    = 3/4 + 40/4 + 2/4

    = 45/4

    3)(3/2+2)(5+1/2)

    = [3/2 + (2 x 2) / (1 x 2)] x [(5 x 2) / (1 x 2) + 1/2]

    = (3/2 + 4/2) x (10/2 + 1/2)

    = 7/2 x 11/12

    = 77/4

    4) 4/5×(5/4+1)-3/10

    = 4/5 x [5/4 + (1 x 4) / (1 x 4)] - 3/10

    = 4/5 x (5/4 + 4/4) - 3/10

    = 4/5 x 9/4 - 3/10

    = 36/20 - 3/10

    = (2 x 18) / (2 x 10) - 3/10

    = 18/10 - 3/10

    = 15/10

    = (5 x 3) / (5 x 2)

    = 3/2.

    5) -5/7+-2/7×1/3

    = - 5/7 - 2/21

    = (- 5 x 3) / (7 x 3) - 2/21

    = - 15/21 - 2/21

    = - 17/21

    6) 8+21×2/3

    = 8 + 42/3

    = 8 + 14

    = 22

    7) 7/3-4/3÷2/5

    = 7/3 - 4/3 x 5/2

    = 7/3 - 20/6

    = 7/3 - (2 x 10) / (2 x 3)

    = 7/3 - 10/3

    = - 3/3

    = - 1

    8) 2/5+3/5+(1-1/10)

    = (2 x 2) / (5 x 2) + (3 x 2) / (5 x 2) + [(1 x 10) / (1 x 10) - 1/10]

    = 4/10 + 6/10 + (10/10 - 1/10)

    = 10/10 + 9/10

    = 19/10.

    9) (1/9-3/5)(8/5+7/9)

    = [(1 x 5) / (9 x 5) - (3 x 9) / (5 x 9)] [(8 x 9) / (5 x 9) + (7 x 5) / (8 x 5)]

    = (5/45 - 27/45) x (72/45 + 35/45)

    = - 22/45 x 2 520/45

    = - 55 440/2 0254

    = (45 x - 1 232) / (45 x 45)

    = - 1 232/45.

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